MPD78
12-17-2009, 09:19 AM
Hello all,
In the field of heat transfer in the mode of radiation there is an integral that can be used find the fraction of the total emission from a blackbody at a certain wave length.
The equation is: (please forgive the notation, my LaTex knowledge is minimal.)
Integrand = (E(lambda of a blackbody) / sigma*T^5 ))
F(0 to lambda) = Integrand d(lambda *T)
The limits of integration are
Lower = 0
Upper = lambda*T
Additional information:
lambda = wavelength (microns)
T = temperature of the blackbody (K)
sigma = Stefan-Boltzman constant = 5.670e-8 (W/m^2-K^4)
E is a function of wavelength and Temperature
Here is the euqation for E:
E(lambda of blackbody, T) = C1 / lambda^5*(exp(C2/lambda*T) - 1)
C1 = 2*PI*h*c^2 = 3.742e8 (W*microns^4 / m^2)
C2 = (h*c/k) = 1.439e4 (microns*K)
From Siegel's book "Thermal Radiation Heat Transfer" the integrand is only a function of the wavelength temperature product.
So basically the integral is set equal to a function f(lambda*T).
A table of the results are given. For example,
f(lambda*T) = 2200 (microns*K) the value of F(0 to lambda) = 0.100888
My question is this;
I am assuming that this integral was solved numerically, but how was that performed? I tried to used qsimp and qtrap but didn't obtain the correct results.
Any help would be greatly appreciated.
See attachment for a much "easier" read of the equations (crudely) described above.
EDIT: I did a quick search of Google books and the newest edition is there with as a limited preview. The solution methodology used to evaluate the function is descibed on pages 21 - 22.
Here is a link to page 21.
http://books.google.com/books?id=O389yQ0-fecC&lpg=PP1&pg=PA21#v=onepage&q=&f=false
END EDIT:
Thanks
Matt
In the field of heat transfer in the mode of radiation there is an integral that can be used find the fraction of the total emission from a blackbody at a certain wave length.
The equation is: (please forgive the notation, my LaTex knowledge is minimal.)
Integrand = (E(lambda of a blackbody) / sigma*T^5 ))
F(0 to lambda) = Integrand d(lambda *T)
The limits of integration are
Lower = 0
Upper = lambda*T
Additional information:
lambda = wavelength (microns)
T = temperature of the blackbody (K)
sigma = Stefan-Boltzman constant = 5.670e-8 (W/m^2-K^4)
E is a function of wavelength and Temperature
Here is the euqation for E:
E(lambda of blackbody, T) = C1 / lambda^5*(exp(C2/lambda*T) - 1)
C1 = 2*PI*h*c^2 = 3.742e8 (W*microns^4 / m^2)
C2 = (h*c/k) = 1.439e4 (microns*K)
From Siegel's book "Thermal Radiation Heat Transfer" the integrand is only a function of the wavelength temperature product.
So basically the integral is set equal to a function f(lambda*T).
A table of the results are given. For example,
f(lambda*T) = 2200 (microns*K) the value of F(0 to lambda) = 0.100888
My question is this;
I am assuming that this integral was solved numerically, but how was that performed? I tried to used qsimp and qtrap but didn't obtain the correct results.
Any help would be greatly appreciated.
See attachment for a much "easier" read of the equations (crudely) described above.
EDIT: I did a quick search of Google books and the newest edition is there with as a limited preview. The solution methodology used to evaluate the function is descibed on pages 21 - 22.
Here is a link to page 21.
http://books.google.com/books?id=O389yQ0-fecC&lpg=PP1&pg=PA21#v=onepage&q=&f=false
END EDIT:
Thanks
Matt